(3/x-4)(x^2-16/9)

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Solution for (3/x-4)(x^2-16/9) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3/x-4)*(x^2-(16/9)) = 0

(3/x-4)*(x^2-16/9) = 0

(3*x^-1-4)*(x^2-16/9) = 0

( 3*x^-1-4 )

3*x^-1 = 4 // : 3

x^-1 = 4/3

-1 < 0

1/(x^1) = 4/3 // * x^1

1 = 4/3*x^1 // : 4/3

3/4 = x^1

x = 3/4

( x^2-16/9 )

1*x^2 = 16/9 // : 1

x^2 = 16/9

x^2 = 16/9 // ^ 1/2

abs(x) = 4/3

x = 4/3 or x = -4/3

x in { 3/4, 4/3, -4/3 }

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